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Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>
#include <ctype.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int i=0;
    while(str[i] != '\0')
    {
        char c = str[i];
        if(( c >= 'a' && c <= 'z') || ( c >= 'A' && c <= 'Z') )
        {
            (*alpha)++;
        }
        else if(( c >= '0' && c <= '9'))
        {
            (*digit)++;
        }
        else if (c != ' ') {
            (*symbol)++;
        }
        i++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2