Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
   int x=0;
   int y=0;
   int z=0;
    while (*str!='\0'){
        if (*str<='9'&&*str>='0'){
            x++;
        }
        else if (((*str<='z')&&(*str>='a'))||((*str<='Z')&&(*str>='A'))){
            y++;
        }
        else if(*str!=32) {
            z++;
        }
        str++;
    }
        *digit=x;
    *alpha=y;
    *symbol=z;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2