Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

bool is_char(char c){
    return (c>='a' && c<='z') || (c>='A' && c<='Z');
}
bool is_num(char c){
    return (c>='0' && c<='9');
}

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int cnt_num = 0, cnt_alp = 0, cnt_sym = 0;
    for(int i=0;str[i] !='\0';i++){
        if(is_char(str[i])) cnt_alp++;
        if(is_num(str[i])) cnt_num++;
        if(!is_char(str[i]) && !is_num(str[i]) && str[i] !=' ') cnt_sym++;
    }
    *alpha = cnt_alp;
    *digit = cnt_num;
    *symbol = cnt_sym;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach