Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

bool is_digit(char str) {
    return ((str >= '0') & (str <= '9')) ? 1 : 0 ;
}

bool is_alpha(char str) {
    return (((str >= 'a') & (str <= 'z')) | ((str >= 'A') & (str <= 'Z'))) ? 1 : 0 ;
}

bool is_symbols(char str) {
    return !is_alpha(str) & !is_digit(str) & (str != ' ') ? 1 : 0;
}

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int i = 0;
    int count_digit = 0;
    int count_alpha = 0;
    int count_symbol = 0;

    while(str[i]) {
        if(is_alpha(str[i])) count_alpha++;
        if(is_digit(str[i])) count_digit++;
        if(is_symbols(str[i])) count_symbol++;
        i++;
    }

    *alpha = count_alpha;
    *digit = count_digit;
    *symbol = count_symbol;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach