Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int i;
    for(i=0; str[i] != '\0'; i++)
    {
        if (str[i] == ' ')
            continue;
        if((str[i] >= 97 && str[i] <= 122) || (str[i] >= 65 && str[i] <= 90))
        {
            (*alpha)++;
        }
        else if(str[i] >= 48 && str[i] <= 57)
        {
            (*digit)++;
        }
        else
            (*symbol)++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach