Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int read = 0;
    while(*(str + read) != '\0'){
        char current_char = *(str + read);
        if(current_char >= 48 && current_char <=57){
            (*digit)++;
        }
         else if ((current_char >= 'A' && current_char <= 'Z') || 
                  (current_char >= 'a' && current_char <= 'z')) {
            (*alpha)++;
        }

         else if((current_char >= 33 && current_char <= 47) ||
                 (current_char >= 58 && current_char <= 64) || 
                 (current_char >= 91 && current_char <= 96) ||
                 (current_char >= 123 && current_char <= 126)
                 ){
            (*symbol)++;
        }
        else{
            //
        }

read++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach