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Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>
#include <string.h>
void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int l=strlen(str);
    for(int i=0;i<l;i++){
        if(((int)str[i]>=65 && (int)str[i]<=90)||
        (((int)str[i]>=97)&&((int)str[i]<=122))){
            *alpha=*alpha+1;
        }
        else if(((int)str[i]>=48)&&((int)str[i]<=57)){
            *digit=*digit+1;
        }
        else{
            if((int)str[i]!=32)
            *symbol=*symbol+1;

        }
    }
    
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2