Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
   uint8_t a = 0, d = 0, s = 0;  

    for (int i = 0; str[i] != '\0'; i++) {
        char ch = str[i];
        if ((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch <= 'z'))
            a++;
        else if (ch >= '0' && ch <= '9')
            d++;
        else if (ch != ' ')
            s++;
    }

    *alpha = a;
    *digit = d;
    *symbol = s;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach