Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    *alpha=0,*digit=0;*symbol=0;
    while(true){
        //printf("%d ",(int)*str);
        if(*str==' '){
            str++;
            continue;
        }
        if(*str=='\0'){
            break;
        }
        else if((97<=(int)*str&&(int)*str<=122)||(65<=(int)*str&&(int)*str<=90)){
            *alpha+=1;
        }
        else if(48<=(int)*str&&(int)*str<=57){
            *digit+=1;
        }
        else{
            *symbol+=1;
        }
        str++;
    }
    //a97 122 z,A65 90 Z,00 99
    //printf("a%d %d z,A%d %d Z,0%d %d9",int('a'),int('z'),int('A'),int('Z'),int('0'),int('9'));
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach