Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int cnt =0;
    *alpha =0;
    *digit =0;
    *symbol = 0;
    while(str[cnt] !=0){
        
        if((str[cnt]> 47) && (str[cnt]<58)){
            (*digit)++;
        }
        else if(((str[cnt]> 64) && (str[cnt]<91)) || ((str[cnt]> 96) && (str[cnt]<123))){
          (*alpha)++;
        }

        else if(str[cnt] != 32){
          (*symbol)++;
        }
        cnt++;
    }
    
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach