Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t count =0;
    for(uint8_t i=0 ; i < 8 ;i ++)
    {
       uint8_t check;
       check = (reg>>i)& 0x01;
       if(check == 1)
       {
        count++;
       }
    }
    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach