Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t cnt=0;
    for(uint8_t i=0;i<=7;i++){

        if(i==0){
            reg==reg>>0;
        }else{
        reg= reg >>1;}
      uint8_t x = reg & 1;  // without all this lines simply can we do if((reg>>i) & 1) 
        if(x==1){
            cnt++;
        }
    }
    return cnt;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach