Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t i, count=0;
    for (i = 0; i < 8; i++)
    {
        if (reg & 1)
            count++;
        reg = reg >> 1;
    }
    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach

start with count=0

check the lsb before shifting right to increment the count or not.

shift right until end of 8 bit register