Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    int count=0;
    uint8_t temp=reg;
   // for(int i=0;i<8;i++){
    while(reg!=0){
        temp  = reg & 0x01;
        if(temp==1){
            count++;
        }
        reg=reg>>1;
    }
    
    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach