Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    int count=0;
   /* for(int i=0;i<8;i++)
    {
        if((reg>>i)&1)
          count++;
    }*/
    while(reg)
    {
        count=count+(reg & 1);
        reg=reg>>1;
    }
    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach