Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    uint8_t count=0;
    for(uint8_t i=0;i<8;i++)
    {
        if(reg&(1<<i))
        {
            count++;
        }
    }
    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach

loop through the 8-bit, and check if its 1 using and operator