Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t nb = 0;
    for(uint8_t i=0 ; i<8; i++){
        if((reg&0x1) == 1){
            nb++;
        }
        reg>>=1;
    }
    return nb;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach