Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    int cnt  = 0, n = 0;
    while (n < 8)
    {
        if ((reg >> n) & 1) cnt++;
        n++;
    }
    return cnt;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach