Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t count = 0;
    if(reg == 0)
    {
        return 0;
    }
    else
    {
        while((reg & reg-1) != 0)
        {
            count++;
            reg &= reg-1;
        }
        count++;
        return count;
    }
    
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach