Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>
int bit,cnt;
uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    cnt=0;
    for(bit=7;bit>=0;bit--)
    {
        if(reg & (1<<bit))
        {
            cnt++;
        }
    }
    return cnt;
}
int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach