Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

#define check_set_bit(n, pos) ((1 << pos) & n)

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t count = 0;
    while(reg>0)
    {
        if(check_set_bit(reg, 0))
        {
            count++;
        }
        reg>>=1;
    }
    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach