Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t count = 0;
    for(int n = 0 ; n < 8 ; n++)
        count += ((reg>>n) & 0x01)? 1 : 0 ;
    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach