Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t x =1;
    uint8_t y=0;
    for(uint8_t i=0;i<8;i++)
    {
        if(x & reg)
        {
            y=y+1;
        }
        x=x<<1;
    }
    return y;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach