Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    uint8_t bit = 0;
    uint8_t cnt = 0;
    for(uint8_t i = 0 ; i < 8; i++)
    {
        bit = (reg >> i) & 0x01;
        if(bit == 1)
        {
            cnt++;
        }
    }
    return cnt;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach