Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    if (reg == 0){
        return 0;
    }
char sbit=0x01;
char count=0;

for(char i=0;i<=7;i++){
if((reg>>i)&sbit==1){
    count++;
}
else 
continue;
}



    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach