Count Set Bits in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t count_set_bits(uint8_t reg) {
    // Your code here
    short int count = 0;
    if(reg & 1){
        count++;
    }
    for(int i = 1; i < 8; i++){
        reg = reg >> 1;
        if(reg & 1){
            count++;
        }
    }
    return count;
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    printf("%u", count_set_bits(reg));
    return 0;
}

Solving Approach