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Code

#include <stdio.h>
#include <stdint.h>

void convert_to_big_endian(uint32_t value, uint8_t arr[4]) {
    // Your code here
    // arr[0] = (value>>24)&0xFF;
    // arr[1] = (value>>16)&0xFF;
    // arr[2] = (value>>8) &0xFF;
    // arr[3] = (value) &0xff; 

    for(int i=0;i<4;i++){
        arr[i] = (value>>(8*(3-i)) & 0xFF);
    }
}

int main() {
    uint32_t value;
    uint8_t arr[4];
    scanf("%u", &value);
    convert_to_big_endian(value, arr);
    for (int i = 0; i < 4; i++) {
        printf("%u", arr[i]);
        if(i<3){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

Step :- 1 iterating the loop 4 times

    for(int i=0;i<4;i++){

        arr[i] = (value>>(8*(3-i)) & 0xFF);

    }

Explanation:-

i=0 :- arr[0] = (value>>24)&0xFF;

i=1:- arr[1] = (value>>16)&0xFF;

i=2 :- arr[2] = (value>>8) &0xFF;

i=3:- arr[3] = (value) &0xFF; 

 

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Input

305419896

Expected Output

18 52 86 120