Code

#include <stdio.h>
#include <stdint.h>

void convert_to_big_endian(uint32_t value, uint8_t arr[4]) {
    arr[0] = (value >> 24) & 0xFF;
    arr[1] = (value >> 16) & 0xFF;
    arr[2] = (value >> 8) & 0xFF;
    arr[3] = value & 0xFF;
}

int main() {
    uint32_t value;
    uint8_t arr[4];
    scanf("%u", &value);
    convert_to_big_endian(value, arr);
    for (int i = 0; i < 4; i++) {
        printf("%u", arr[i]);
        if(i<3){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

  • Shift the 32-bit integer right by 24, 16, 8, and 0 bits to access each byte.
  • Mask with 0xFF to isolate the lowest 8 bits.
  • Store them in the array in MSB → LSB order.
  • Print each byte in decimal (or hex if needed).

 

 

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Input

305419896

Expected Output

18 52 86 120