Decode ADC Result Using Union Bitfields

Code

#include <stdio.h>
#include <stdint.h>

typedef union {
    struct {            // here this structure is anonymous struct
        uint16_t adc_value : 12;
        uint16_t channel   : 4;
    };
    uint16_t adc_reg;
} ADC_Result;

int main() {
    uint16_t reg;
    scanf("%hx", &reg);

    // Fill union and print channel and adc_value
    ADC_Result adc;
    adc.adc_reg = reg;

    printf("Channel: %d\nADC Value: %d", adc.channel, adc.adc_value);
    return 0;
}

Solving Approach

#include <stdio.h>
#include <stdint.h>

typedef union {
    struct {            // here this structure is anonymous struct
        uint16_t adc_value : 12;
        uint16_t channel   : 4;
    };
    uint16_t adc_reg;
} ADC_Result;

int main() {
    uint16_t reg;
    scanf("%hx", &reg);

    // Fill union and print channel and adc_value
    ADC_Result adc;
    adc.adc_reg = reg;

    printf("Channel: %d\nADC Value: %d", adc.channel, adc.adc_value);
    return 0;
}

 

 

Upvote
Downvote
Loading...

Input

0xC3F5

Expected Output

Channel: 12 ADC Value: 1013