#include <stdio.h>
#include <stdint.h>
void decode_status(uint8_t status_reg) {
// Your logic here
for(int current_bit = 0; current_bit < 8; current_bit++){
// Checks if the current bit is 0, if so, skip
if(((status_reg & (1<<current_bit)) >> current_bit )== 0) continue;
// If curren bit is 1, using the current bit position, print out the status
switch(current_bit){
case 0:
printf("Power On\n");
break;
case 1:
printf("Error\n");
break;
case 2:
printf("Tx Ready\n");
break;
case 3:
printf("Rx Ready\n");
break;
case 4:
printf("Overheat\n");
break;
case 5:
printf("Undervoltage\n");
break;
case 6:
printf("Timeout\n");
break;
case 7:
printf("Reserved\n");
break;
}
}
}
int main() {
uint8_t reg;
scanf("%hhu", ®);
decode_status(reg);
return 0;
}Solving Approach
Checks if the current bit is 1 or 0 and proceeds depending on the result. Skips if it's 0, checks what status if 1.
Input
13
Expected Output
Power On Tx Ready Rx Ready