Decode Status Register into Human-Readable Flags

Code

#include <stdio.h>
#include <stdint.h>

void decode_status(uint8_t status_reg) {
    // Your logic here
    const char *flags[8] = {
        "Power On","Error","Tx Ready","Rx Ready","Overheat","Undervoltage","Timeout","Reserved"
    };
    int i;
    for(i = 0;i<8;i++)
    {
        if((status_reg>>i)&0x01)
        {
            printf("%s\n",flags[i]);
        }
    }
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    decode_status(reg);
    return 0;
}

Solving Approach

1. Loop through each bit from 0 to 7 and check if it’s set using (status_reg >> i) & 0x01.
2. If the bit is set, print the corresponding flag name from a predefined array indexed by bit position.