#include <stdio.h> #include <stdint.h> void decode_status(uint8_t status_reg) { // Your logic here const char* bitMap[] = { "Power On", "Error", "Tx Ready", "Rx Ready", "Overheat", "Undervoltage", "Timeout", "Reserved" }; uint8_t reg = status_reg; for(int i = 0; i < 8; i++) { if(reg & (1 << i)) { printf("%s\n", bitMap[i]); } } } int main() { uint8_t reg; scanf("%hhu", ®); decode_status(reg); return 0; }
Solving Approach :
So basically I have tabularized all the bits and its corresponding meanings into one const char* bitMap so that this cannot be modified
Test Cases
Test Results
Input
13
Expected Output
Power On Tx Ready Rx Ready