Decode Status Register into Human-Readable Flags

Code

#include <stdio.h>
#include <stdint.h>

char status[8][20] = {"Power On", "Error", "Tx Ready", 
                        "Rx Ready", "Overheat","Undervoltage", 
                        "Timeout","Reserved"};

void decode_status(uint8_t status_reg) {
    for (int bit = 0; bit <8; bit++){
        if (((status_reg & (1<<bit))>>bit) == 1){
            printf("%s\n", status[bit]);
        }
    }
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    decode_status(reg);
    return 0;
}

Solving Approach

We need to loop through each bit in the status register and check which bits are by using the AND & operator and right shift it to read the bit. Because we have to print flag name, we will store the names in a string array and print according to the bit and array index.