#include <stdio.h> #include <stdint.h> void decode_status(uint8_t status_reg) { // Your logic here char str[8][15]={"Power On", "Error", "Tx Ready", "Rx Ready", "Overheat", "Undervoltage", "Timeout", "Reserved"}; uint8_t arr[7]={0}; uint8_t i = 0; uint8_t du = 0; while(status_reg / 2 != 0) { du = status_reg % 2; status_reg = status_reg / 2 ; arr[i] = du ; i++; } arr[i++] = 1; for(uint8_t j = 0 ; j < 8; j++) { if(arr[j] == 1) { printf("%s\n",str[j]); } } } int main() { uint8_t reg; scanf("%hhu", ®); decode_status(reg); return 0; }
Solving Approach
Test Cases
Test Results
Input
13
Expected Output
Power On Tx Ready Rx Ready