Decode Status Register into Human-Readable Flags

Code

#include <stdio.h>
#include <stdint.h>

static char *flag_status_meaning[8] = {"Power On", "Error", "Tx Ready", "Rx Ready", "Overheat", "Undervoltage",
                            "Timeout", "Reserved"};

void decode_status(uint8_t status_reg) {
    // Your logic here
    uint8_t flag_status = status_reg;

    for(int i = 0; i < 8; ++i)
    {
        if((flag_status & 1U))
        {
            printf("%s\n", flag_status_meaning[i]);
        }
        flag_status >>= 1U; 
    }
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    decode_status(reg);
    return 0;
}

Solving Approach

Req:
- map the flags to the bit position
- return what is set

0 - 255
0 -> return nothing
255 -> all the flags are set

Plan:
- keep shifting to the right and take & with 1U
- if the above is 1 then as per the iteration print the flag
- if not then skip or print nothing