#include <stdio.h> #include <stdint.h> void decode_status(uint8_t status_reg) { // Your logic here int i=0; char efn[8][20]={"Power On","Error","Tx Ready","Rx Ready","Overheat","Undervoltage","Timeout","Reserved"}; for (i;i<8;i++) { if(status_reg>>i&1) { printf("%s\n",efn[i]); } } } int main() { uint8_t reg; scanf("%hhu", ®); decode_status(reg); return 0; }
Solving Approach
Test Cases
Test Results
Input
13
Expected Output
Power On Tx Ready Rx Ready