Decode Status Register into Human-Readable Flags

#include <stdio.h>
#include <stdint.h>

void decode_status(uint8_t status_reg) {
    // Your logic here
    const char status[8][16] {
        "Power On",
        "Error",
        "Tx Ready",
        "Rx Ready",
        "Overheat",
        "Undervoltage",
        "Timeout",
        "Reserved"
    };

    for(int i = 0; i < 8; i++) {
        if(status_reg & (1 << i)) {
            printf("%s\n", status[i]);
        }
    }
}

int main() {
    uint8_t reg;
    scanf("%hhu", &reg);
    decode_status(reg);
    return 0;
}

Solving Approach

• Using an array to jot down status
• Use plain for loop for it
• It looks cleaner this way than a bunch of if statement