Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    //return 0;
    for(int i=0;i<k;i=i+2){
        if(*mem!=*(mem+i)){
            return 0;
        }
    }

    for(int i=1;i<k;i=i+2){
        if(*(mem+1)!=*(mem+i)){
            return 0;
        }
    }
    return 1;

}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach

check the values at odd and even place upto k mem locations, if same return 1;