Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    int* even = mem;
    int* odd = mem + 1;

    for(int i=0; i<k; i++)
    {
        if(i%2 == 0) //even
        {
            if(*even != *(mem + i))
            {
                return 0;
            }
        }
        else //odd
        {
            if(*odd != *(mem + i))
            {
                return 0;
            }
        }
    }
    return 1;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach