Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    int *curr = mem;
    int expected = *curr;  // starting value: either 0 or 1

    for (int i = 0; i < k; i++) {
        if (*curr != expected) {
            return 0;
        }
        expected = 1 - expected;  // alternate expectation
        curr++;  // move pointer forward
    }
    return 1;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach