Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    int i;
    int ok = 0;
    int cnt = 1;
    for (i = 0; i<k && ok == 0 && cnt == 1; i++){
        if(*(mem+i) == 0){
            if((*(mem+i+1) == 1) && (*(mem+i+2) == 0)) ok = 1;
            else {
                ok = 0;
                cnt ++;
            }
        }
        else if(*(mem+i) == 1){
            if((*(mem+i+1) == 0 && (*(mem+i+2) == 1))) ok = 1;
            else {
                ok = 0;
                cnt ++;
            }
        }
    }
    return ok;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach