Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    int *p = mem;
    for(int i = 1; i<k-1; i++)
    {
        if(*(p+i)==*(p+i-1))
        {
            return 0;
        }
    }
    return 1;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach

• assign the starting address of the array to a pointer

• iterate a loop from i=1 to i=k-1

  at each step compare  *(p+1) == *(p+i-1)  if equal chain breaks then return 0

• when loop terminates return 1