Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    int *e1= mem;
    int *e2 = mem+1;
    for (int l = 0; l < k; l++){
        if ((l % 2) == 0) {  //parzysty l
            if (!(*e1==*(mem+l))) break;
        }  
        else {//nieparzysty l = sprawdzamy e1
            if (!(*e2==*(mem+l))) break;
        }
        if (l==(k-1)) return 1;
        }
    return 0;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach