Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    int count = 0;
    for(int i = 1; i<k; i++){
    	int pattern = *(mem + i) ^ *(mem + i - 1);
    	if(pattern == 1){count++;}
    	else{count = 0;}
    	if(count == k-1){return 1;}

    }
    return 0;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach