Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int n, int k) {
    // Write your pointer logic here
    for (int i = 0; i < n-k+1; i++) {
        int flag = 0;
        for (int j = i; j < i+k-1; j++) {
            if ((*mem+j) == *(mem+j+1)) {
                flag = 1;
            }
        } 
        if (flag == 0) {
            return 1;
        }
    }
    return 0;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, n, k);
    printf("%d", res);

    return 0;
}

Solving Approach