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Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    if (k <= 1) return 1; // Single element is trivially alternating
    int *prev = mem;
    int *next = mem+1;
    while(k>1)
    {
        if(0 == (*prev)^(*next))
        {
            return 0;
        }
        prev++;
        next++;
        k--;
    }
    return 1;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach

 

 

 

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Input

6 6 1 0 1 0 1 0

Expected Output

1