Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    for(int i = 1 ; i < k ; i++){
        if(*( mem + i ) == *( mem + i - 1 )){
            return 0;
        }
        
    }
    return 1;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach

• Take first element as your starting point → *mem
• Loop from second element (i = 1) to k - 1
• For every element:
  • Compare it with the previous element using pointer arithmetic
    → *(mem + i) and *(mem + i - 1)
  • If both are same, pattern is broken → return 0
• If loop completes, return 1 (means pattern is alternating)