Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    int *p=mem,flag=1;
    
    for(int i=0;i<k-1;i++,p++){
        if((*p==0 && *(p+1)==1)||(*p==1 && *(p+1)==0)){
            flag=0;
        }else{
            flag=1;
            break;
        }
    }
    if(flag==0) return 1;
    else return 0;
    
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach

 

 

 

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Input

6 6 1 0 1 0 1 0

Expected Output

1