Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    volatile int c;
   if (*mem==1){
    int *p1=mem;
    int *p2=mem+1;
    c=1;
      for(int i=0;i<k/2;i++){
        if(*p1==1&&*p2==0){
       c=1;
        }else{
          c=0;
        }
        
        p1+=2;
        p2+=2;
      }
      return c;
   }
   else{
int *p1=mem;
    int *p2=mem+1;
    c=1;
      for(int i=0;i<k/2;i++){
        if(*p1==0&&*p2==1){
       c=1;
        }else{
          c=0;
        }
        
        p1+=2;
        p2+=2;
      }
      return c;
   }
    return c;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach

 

 

 

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Input

6 6 1 0 1 0 1 0

Expected Output

1