#include <stdio.h>
int is_alternating_pattern(int *mem, int k) {
// Write your pointer logic here
bool curr; //works because seq is 0 and 1
while(--k){
curr = (bool)*mem;
if(curr == *(mem+1)) return 0; //can replace with 1-curr
mem++;
}
/*
while(--k){
if(*mem == *(++mem)) return 0;
}
*/
return 1;
}
int main() {
int n, k, arr[100];
scanf("%d %d", &n, &k);
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int res = is_alternating_pattern(arr, k);
printf("%d", res);
return 0;
}check if the next element is alternate, use *(mem+1).
Input
6 6 1 0 1 0 1 0
Expected Output
1